(x+2)[x+(-2)]=0

Solution for (x+2)[x+(-2)]=0 equation:

Simplifying
(x + 2)[x + (-2)] = 0

Reorder the terms:
(2 + x)[x + (-2)] = 0
(2 + x)[x + -2] = 0

Reorder the terms:
(2 + x)[-2 + x] = 0

Multiply (2 + x) * [-2 + x]
(2[-2 + x] + x[-2 + x]) = 0
([-2 * 2 + x * 2] + x[-2 + x]) = 0
([-4 + 2x] + x[-2 + x]) = 0
(-4 + 2x + [-2 * x + x * x]) = 0
(-4 + 2x + [-2x + x2]) = 0

Combine like terms: 2x + -2x = 0
(-4 + 0 + x2) = 0
(-4 + x2) = 0

Solving
-4 + x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + x2 = 0 + 4
x2 = 0 + 4

Combine like terms: 0 + 4 = 4
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}